[
  {
    "step": 632,
    "title": "Freeze the calendar-half source family",
    "question": "What complete source packet is needed before testing File70’s three calendar bridges?",
    "inputs": {
      "restored_Creation_rail": [
        4251,
        4244,
        4237
      ],
      "standard_Creation_rail": [
        4121,
        4114,
        4107
      ],
      "exposure_nodes": [
        4238,
        4108
      ],
      "Joseph_birth_descent_elevation": [
        1915,
        1898,
        1885
      ],
      "Joseph_rail": [
        1885,
        1878,
        1871
      ],
      "regular_Cainan_difference": 130
    },
    "sources": [
      "File70 §§6.1–6.7; source state register"
    ],
    "opened_utc": "2026-09-28T00:56:25.987258+00:00",
    "predecessor_sha256": "C631:8da995fbc41dba4a3b78b59a6a6a316b712980b5052087bc963cd75e15db6351",
    "results": {
      "packet": {
        "path": "model/calendar_half_inputs.json",
        "sha256": "c3794e48f499ce37b49dfc94f7ead80771e50a487e4331f9c599e8e537886578",
        "bytes": 975
      },
      "primary_registers": {
        "Prophetic": [
          4238,
          1898,
          13,
          180
        ],
        "Priestly": [
          4237,
          1885,
          14,
          168
        ],
        "Enochian": [
          4251,
          1885,
          13,
          182
        ]
      }
    },
    "finding": "The complete packet fixes two Creation states, Joseph’s corresponding nodes, and the three13/14/13 half-year counts before calculation. The test can now explain the family from one labelled geometry.",
    "reassessment": "Generate the corresponding-node translation of the two seven-plus-seven rails.",
    "checks": {
      "source_section_present": true,
      "named_source_nodes": true
    },
    "closed_utc": "2026-09-28T00:56:25.988288+00:00",
    "sha256": "eeece7023cc8386382b385b9ec212f6eef1a499feaea2261e04d13592d5f4f4e"
  },
  {
    "step": 633,
    "title": "Generate the corresponding Creation–Joseph rail map",
    "question": "Do the two source seven-plus-seven rails require more than one translation?",
    "inputs": {
      "Creation": [
        4251,
        4244,
        4237
      ],
      "Joseph": [
        1885,
        1878,
        1871
      ]
    },
    "sources": [
      "File70 §6.3"
    ],
    "opened_utc": "2026-09-28T00:56:54.571747+00:00",
    "predecessor_sha256": "eeece7023cc8386382b385b9ec212f6eef1a499feaea2261e04d13592d5f4f4e",
    "results": {
      "corresponding_spans": [
        2366,
        2366,
        2366
      ],
      "rail_gaps": [
        [
          7,
          7
        ],
        [
          7,
          7
        ]
      ],
      "translation": 2366
    },
    "finding": "One translation of2366 carries all three source nodes and preserves the7+7 partition. The three matches are dependent coordinates of one rigid relation.",
    "reassessment": "Generate every cross-rail span to distinguish the special diagonals from the whole family.",
    "checks": {
      "translation": true,
      "shape": true
    },
    "closed_utc": "2026-09-28T00:56:54.571916+00:00",
    "sha256": "0546e755ab9dd83737899b935cd48b0288025b0ea9210c04ce267c96aa61c6e8"
  },
  {
    "step": 634,
    "title": "Generate the full cross-rail matrix",
    "question": "Does one indexed formula account for all nine span comparisons?",
    "inputs": {
      "head_difference": 2366,
      "rail_step": 7,
      "indices": [
        0,
        1,
        2
      ]
    },
    "sources": [
      "File70 §§6.3,6.5; derived completion of source geometry"
    ],
    "opened_utc": "2026-09-28T00:57:07.226648+00:00",
    "predecessor_sha256": "0546e755ab9dd83737899b935cd48b0288025b0ea9210c04ce267c96aa61c6e8",
    "results": {
      "span_matrix": [
        [
          2366,
          2373,
          2380
        ],
        [
          2359,
          2366,
          2373
        ],
        [
          2352,
          2359,
          2366
        ]
      ],
      "multiplicities": {
        "2352": 1,
        "2359": 2,
        "2366": 3,
        "2373": 2,
        "2380": 1
      },
      "formula": "D(i,j)=2366+7(j−i)",
      "source_selected_extremes": [
        2352,
        2366,
        2380
      ]
    },
    "finding": "The complete matrix has five span values with multiplicities1,2,3,2,1. Minimum, corresponding and maximum spans are2366−14,2366,2366+14; the other entries are generated comparisons, not additional source appointments.",
    "reassessment": "Explain the separate exposure span using its two thirteen-year flanks.",
    "checks": {
      "extremes": true,
      "frequency": true,
      "matrix_from_dates": true
    },
    "closed_utc": "2026-09-28T00:57:07.226929+00:00",
    "sha256": "3bef9066b0c13130bfd753799a43e2aaee36086aa9fcaf0f767da80df7c64879"
  },
  {
    "step": 635,
    "title": "Reconstruct the exposure bridge from its flanks",
    "question": "How does the13+2340+13 path relate to the corresponding2366 translation?",
    "inputs": {
      "path": [
        4251,
        4238,
        1898,
        1885
      ]
    },
    "sources": [
      "File70 §§6.1,6.4"
    ],
    "opened_utc": "2026-09-28T00:57:18.616719+00:00",
    "predecessor_sha256": "3bef9066b0c13130bfd753799a43e2aaee36086aa9fcaf0f767da80df7c64879",
    "results": {
      "partition": [
        13,
        2340,
        13
      ],
      "total": 2366,
      "calendar_difference": 26,
      "Joseph_ages": [
        17,
        30
      ]
    },
    "finding": "The source path supplies13-year flanks around2340, giving2366. The26 added years are exactly6.5 copies of the360-to364 calendar difference. Joseph’s ages17 and30 provide the same13-year lower flank.",
    "reassessment": "Compare all three calendar spans under their own calibrated Keys.",
    "checks": {
      "partition": true,
      "calendar_gain": true,
      "ages": true
    },
    "closed_utc": "2026-09-28T00:57:18.617072+00:00",
    "sha256": "d4fba769a5c3e22462d9fe6614b02309624c1ab71009705221d66170acf86e66"
  },
  {
    "step": 636,
    "title": "Normalize the three calendar registers",
    "question": "Do the three spans become one common output under their respective Keys?",
    "inputs": {
      "spans": [
        2340,
        2352,
        2366
      ],
      "days": [
        360,
        336,
        364
      ],
      "Keys": [
        "70/69",
        "25/23",
        "300/299"
      ]
    },
    "sources": [
      "File70 §6.7; C586 calendar calibration"
    ],
    "opened_utc": "2026-09-28T00:57:35.899669+00:00",
    "predecessor_sha256": "d4fba769a5c3e22462d9fe6614b02309624c1ab71009705221d66170acf86e66",
    "results": {
      "normalized_year_counts": [
        "13/2",
        7,
        "13/2"
      ],
      "Key_outputs": [
        "54600/23",
        "58800/23",
        "54600/23"
      ],
      "output_ratio": "13:14:13",
      "half_year_unit": "4200/23"
    },
    "finding": "The Prophetic and Enochian arms normalize to6.5 calendar years; the Priestly arm to7. Their outputs are13,14,13 copies of one calibrated half-year. The family preserves two count classes, not one undifferentiated result.",
    "reassessment": "Determine what equal transformed spans imply when their held heads differ.",
    "checks": {
      "normalization": true,
      "outputs": true,
      "two_classes": true
    },
    "closed_utc": "2026-09-28T00:57:35.899892+00:00",
    "sha256": "17fb6bac910067917df66b14db474b381af070138efcdb0c206f8674725e9eef"
  },
  {
    "step": 637,
    "title": "Carry normalized equality into anchored placement",
    "question": "Do equal Prophetic and Enochian outputs imply an identical dated endpoint here?",
    "inputs": {
      "Prophetic_head": 4238,
      "Enochian_head": 4251,
      "common_output": "54600/23"
    },
    "sources": [
      "File70 source endpoints; derived anchored-Key diagnostic"
    ],
    "opened_utc": "2026-09-28T00:57:45.785330+00:00",
    "predecessor_sha256": "17fb6bac910067917df66b14db474b381af070138efcdb0c206f8674725e9eef",
    "results": {
      "Prophetic_generated_endpoint": "42874/23",
      "Enochian_generated_endpoint": "43173/23",
      "endpoint_difference": 13,
      "frame_adjusted_Enochian_endpoint": "42874/23"
    },
    "finding": "The generated endpoints differ13 because the held heads differ13. Translating the Enochian output frame by−13 aligns them. Equal normalized spans explain the shape; source anchor differences explain its placement. These fractional outputs are diagnostics, not adopted event dates.",
    "reassessment": "Derive why the Priestly minimum has fourteen half-year units.",
    "checks": {
      "difference": true,
      "frame_relation": true
    },
    "closed_utc": "2026-09-28T00:57:45.785544+00:00",
    "sha256": "6913761b17e777dff8eec192689d88922a0dcae2329697f6ae654fe48fddd2c4"
  },
  {
    "step": 638,
    "title": "Explain the Priestly minimum by factor structure",
    "question": "Why does subtracting the14-year rail width from13×182 produce14×168?",
    "inputs": {
      "corresponding_count": 13,
      "Enochian_half": 182,
      "rail_width": 14
    },
    "sources": [
      "File70 §§6.2–6.5"
    ],
    "opened_utc": "2026-09-28T00:57:56.936051+00:00",
    "predecessor_sha256": "6913761b17e777dff8eec192689d88922a0dcae2329697f6ae654fe48fddd2c4",
    "results": {
      "corresponding_factorization": [
        14,
        169
      ],
      "minimum_factorization": [
        14,
        168
      ],
      "Priestly_half": 168,
      "identity": "13×182−14=14(169−1)=14×168"
    },
    "finding": "The Priestly minimum follows from182=14×13 and168=13²−1. The common14-year width turns the corresponding vector into fourteen Priestly halves. This explains the change from13 to14 calendar units through the rail geometry.",
    "reassessment": "Test whether the combined half-calendar conditions select a unique count or a congruence family.",
    "checks": {
      "factorization": true,
      "minimum": true,
      "difference_of_squares": true
    },
    "closed_utc": "2026-09-28T00:57:56.936249+00:00",
    "sha256": "48e03ab500abe657bfcd30dd81ee12ec3744e5ab24b2d6c021bf1052845dc452"
  },
  {
    "step": 639,
    "title": "Solve the two-calendar compatibility equation",
    "question": "What count family permits an Enochian corresponding span and a Priestly minimum fourteen years shorter?",
    "inputs": {
      "equation": "182m−14=168n",
      "positive_integer_counts": true
    },
    "sources": [
      "Derived from File70 §6 source geometry"
    ],
    "opened_utc": "2026-09-28T00:58:22.881303+00:00",
    "predecessor_sha256": "48e03ab500abe657bfcd30dd81ee12ec3744e5ab24b2d6c021bf1052845dc452",
    "results": {
      "reduced_equation": "13m−12n=1",
      "general_solution": "m=1+12q; n=1+13q",
      "examples_m_n": [
        [
          1,
          1
        ],
        [
          13,
          14
        ],
        [
          25,
          27
        ],
        [
          37,
          40
        ]
      ],
      "source_choice_q": 1
    },
    "finding": "The pair of calendar requirements has an infinite integer family. Its source member is m=13,n=14; the smaller m=n=1 also fits the two-calendar equation. The exposure condition must supply any stronger selection.",
    "reassessment": "Add the fixed thirteen-year exposure flanks and solve the complete three-calendar system.",
    "checks": {
      "examples": true,
      "source_member": true,
      "not_unique_pair": true
    },
    "closed_utc": "2026-09-28T00:58:22.881481+00:00",
    "sha256": "2d75bc9bfb77ad832fbb24b55007d44225e7432b192eeef77c2166cdfd940f33"
  },
  {
    "step": 640,
    "title": "Solve the complete three-calendar congruence family",
    "question": "Do the fixed fourteen-year rail and thirteen-year flanks select the source count triple as the smallest positive solution?",
    "inputs": {
      "conditions": [
        "T=182m",
        "T−14=168n",
        "T−26=180p"
      ],
      "counts": "positive integers"
    },
    "sources": [
      "File70 §6 geometry; derived integer compatibility theorem"
    ],
    "opened_utc": "2026-09-28T00:58:46.567888+00:00",
    "predecessor_sha256": "2d75bc9bfb77ad832fbb24b55007d44225e7432b192eeef77c2166cdfd940f33",
    "results": {
      "m_residue_mod180": [
        13
      ],
      "general_T": "2366+32760q",
      "general_counts": "m=13+180q; n=14+195q; p=13+182q",
      "examples": [
        {
          "q": 0,
          "T": 2366,
          "m": 13,
          "n": 14,
          "p": 13
        },
        {
          "q": 1,
          "T": 35126,
          "m": 193,
          "n": 209,
          "p": 195
        },
        {
          "q": 2,
          "T": 67886,
          "m": 373,
          "n": 404,
          "p": 377
        }
      ],
      "least_positive_solution": [
        2366,
        13,
        14,
        13
      ]
    },
    "finding": "With the source offsets fixed, the full system has T=2366+32760q. Its least positive solution is exactly the source2366 and13/14/13 half-count triple. This is a conditional local minimality result, not a claim of a globally minimal chronology.",
    "reassessment": "Relate the congruence period to the calendar lattice, then test the source no-Cainan companion.",
    "checks": {
      "fundamental_residue": true,
      "all_three_equations": true,
      "least_positive": true
    },
    "closed_utc": "2026-09-28T00:58:46.568078+00:00",
    "sha256": "623fd5df259934d6c3ff7cec267048b2c6c0b361546a0a0f59ddddd9c1f4a956"
  },
  {
    "step": 641,
    "title": "Identify the calendar compatibility period",
    "question": "Why is the full congruence period32760, and how does it meet the earlier common-volume family?",
    "inputs": {
      "half_calendars": [
        168,
        180,
        182
      ],
      "full_calendars": [
        336,
        360,
        364
      ]
    },
    "sources": [
      "C640; File12 calendar definitions; C575"
    ],
    "opened_utc": "2026-09-28T00:58:58.617439+00:00",
    "predecessor_sha256": "623fd5df259934d6c3ff7cec267048b2c6c0b361546a0a0f59ddddd9c1f4a956",
    "results": {
      "half_calendar_lcm": 32760,
      "full_calendar_lcm": 65520,
      "previous_volume_coefficient": 327600,
      "ratios": [
        2,
        10
      ]
    },
    "finding": "The period32760 is the least common multiple of the three half-calendars. Doubling gives65520 for full calendars; the earlier327600 common-volume coefficient is ten half-periods. The numerical link comes from the same calendar denominators, with units retained.",
    "reassessment": "Execute the no-Cainan rail companion and locate which calendar divisibilities it preserves.",
    "checks": {
      "period": true,
      "previous_volume": true,
      "counts_increment": true
    },
    "closed_utc": "2026-09-28T00:58:58.617609+00:00",
    "sha256": "aca507fc8cb4d8a7ff368876b5cf8e91a3c68205120bedafce3f964c098b542e"
  },
  {
    "step": 642,
    "title": "Reconstruct the no-Cainan companion",
    "question": "Which relations survive when the Creation rail alone moves130?",
    "inputs": {
      "standard_Creation": [
        4121,
        4114,
        4107
      ],
      "Joseph": [
        1885,
        1878,
        1871
      ],
      "standard_exposure": 4108
    },
    "sources": [
      "File70 §§6.1,6.6"
    ],
    "opened_utc": "2026-09-28T00:59:33.175668+00:00",
    "predecessor_sha256": "aca507fc8cb4d8a7ff368876b5cf8e91a3c68205120bedafce3f964c098b542e",
    "results": {
      "span_family": [
        2210,
        2222,
        2236,
        2250
      ],
      "corresponding_spans": [
        2236,
        2236,
        2236
      ],
      "calendar_half_counts": [
        "221/18",
        "1111/84",
        "86/7"
      ],
      "shift_from_restored": 130
    },
    "finding": "Removing130 preserves both7+7 rails and all their relative diagonals, giving2236 as the corresponding translation. It changes the calendar counts to nonintegers, so the restored state’s13/14/13 specialization is not automatic from rail shape alone.",
    "reassessment": "Ask whether the fixed standard state and three-calendar conditions select130 as the least nonnegative correction.",
    "checks": {
      "companion": true,
      "shape": true,
      "counts_changed": true
    },
    "closed_utc": "2026-09-28T00:59:33.175833+00:00",
    "sha256": "bfffe3745aa25cf6e552ea3071d48994bddd5bd76620a6756efff51414405fdc"
  },
  {
    "step": 643,
    "title": "Solve the source-state correction congruence",
    "question": "Given the standard2236 vector, what correction first enters the complete calendar-compatible class?",
    "inputs": {
      "standard_vector": 2236,
      "compatible_class": "2366+32760q",
      "permitted_test": "nonnegative integer correction to Creation rail only"
    },
    "sources": [
      "C640,C642; File70 regular Cainan comparison"
    ],
    "opened_utc": "2026-09-28T00:59:50.845969+00:00",
    "predecessor_sha256": "bfffe3745aa25cf6e552ea3071d48994bddd5bd76620a6756efff51414405fdc",
    "results": {
      "correction_class": "130+32760q",
      "least_nonnegative": 130,
      "examples": [
        130,
        32890,
        65650
      ],
      "source_regular_Cainan": 130
    },
    "finding": "With the standard vector and the14/26 offsets fixed, the least nonnegative correction satisfying all three calendar conditions is130. This recovers the supplied regular-Cainan increment conditionally; it does not infer an insertion history or change the frozen MT state.",
    "reassessment": "Use the supplied Enoch close to reconstruct the Priestly minimum’s internal partition.",
    "checks": {
      "least": true,
      "compatible": true
    },
    "closed_utc": "2026-09-28T00:59:50.846140+00:00",
    "sha256": "2d76bad693f618f2534e23e922c8d6ae92c4cca38f6b11bd4c7b6dc807d3a113"
  },
  {
    "step": 644,
    "title": "Recover the Enoch partition of the Priestly minimum",
    "question": "What additional placement does the appendix’s supplied Enoch close contribute?",
    "inputs": {
      "path": [
        4237,
        3257,
        1885
      ],
      "Enoch_status": "pre-existing secondary source comparison; no Gear transport"
    },
    "sources": [
      "File70 Appendix D.2–D.4"
    ],
    "opened_utc": "2026-09-28T01:00:01.628554+00:00",
    "predecessor_sha256": "2d76bad693f618f2534e23e922c8d6ae92c4cca38f6b11bd4c7b6dc807d3a113",
    "results": {
      "partition": [
        980,
        1372
      ],
      "jubilee49_coefficients": [
        20,
        28
      ],
      "primitive196_coefficients": [
        5,
        7
      ],
      "whole": 2352
    },
    "finding": "The supplied Enoch close partitions2352 as980+1372, or20+28 jubilee49 units. The reduced ratio is5:7. The total follows from the rail geometry; this particular internal cut depends on the separately supplied3257 role.",
    "reassessment": "Test the corresponding Enoch head to identify which part of the partition is role-specific.",
    "checks": {
      "partition": true,
      "total": true,
      "ratio": true
    },
    "closed_utc": "2026-09-28T01:00:01.628730+00:00",
    "sha256": "c26f666a0f60b1a78231c0ab16fe7c353022d0aa312dbcfb172e373a516d55a2"
  },
  {
    "step": 645,
    "title": "Test the Enoch partition role",
    "question": "Does the supplied Enoch head give the same internal partition as its close?",
    "inputs": {
      "head": 3264,
      "close": 3257,
      "outer": [
        4237,
        1885
      ]
    },
    "sources": [
      "File70 Appendix D.1–D.4",
      "C644"
    ],
    "opened_utc": "2026-09-28T01:03:53.595962+00:00",
    "predecessor_sha256": "c26f666a0f60b1a78231c0ab16fe7c353022d0aa312dbcfb172e373a516d55a2",
    "results": {
      "head_partition": [
        973,
        1379
      ],
      "close_partition": [
        980,
        1372
      ],
      "head_49_coefficients": [
        "139/7",
        "197/7"
      ]
    },
    "finding": "Replacing the supplied close with the head transfers seven years between the two arms and preserves2352. The5:7 partition belongs to the close role; it is not a property of any Enoch placement.",
    "reassessment": "Recover the complete two-node Enoch comparison from its seven-year rails.",
    "checks": {
      "head": true,
      "transfer": true,
      "total": true
    },
    "closed_utc": "2026-09-28T01:03:53.596210+00:00",
    "sha256": "5051984995800a79412c616ea15b3a8e1034afce5a7ba02b08e6e0c5e5898ca9"
  },
  {
    "step": 646,
    "title": "Generate the Creation–Enoch rail square",
    "question": "Can one translation recover all four admitted Creation–Enoch spans?",
    "inputs": {
      "upper": [
        4244,
        4237
      ],
      "lower": [
        3264,
        3257
      ]
    },
    "sources": [
      "File70 Appendix D.1"
    ],
    "opened_utc": "2026-09-28T01:04:02.788349+00:00",
    "predecessor_sha256": "5051984995800a79412c616ea15b3a8e1034afce5a7ba02b08e6e0c5e5898ca9",
    "results": {
      "matrix": [
        [
          980,
          987
        ],
        [
          973,
          980
        ]
      ],
      "translation": 980,
      "rail": 7
    },
    "finding": "The four comparisons are one seven-year rail translated by980: corresponding980s and crossed973/987. This reuses the same rail generator as the larger calendar family.",
    "reassessment": "Ask whether the source’s nested14/140/980 spans share one normalized shape.",
    "checks": {
      "whole_matrix": true,
      "entries": true
    },
    "closed_utc": "2026-09-28T01:04:02.788514+00:00",
    "sha256": "e43acebadfd5a87cfe91676d5933ebd599a2af327f809f6ec2b87cd1f3b4a4bc"
  },
  {
    "step": 647,
    "title": "Normalize the nested bilateral spans",
    "question": "What structure is shared by the source’s14,140 and980 layers?",
    "inputs": {
      "widths": [
        14,
        140,
        980
      ],
      "halves": [
        7,
        70,
        490
      ]
    },
    "sources": [
      "File70 Appendix D.5"
    ],
    "opened_utc": "2026-09-28T01:04:13.636096+00:00",
    "predecessor_sha256": "e43acebadfd5a87cfe91676d5933ebd599a2af327f809f6ec2b87cd1f3b4a4bc",
    "results": {
      "normalized_halves": [
        [
          1,
          1
        ],
        [
          1,
          1
        ],
        [
          1,
          1
        ]
      ],
      "scale_from14": [
        1,
        10,
        70
      ]
    },
    "finding": "The three layers share the bilateral1|1 shape at scales1,10,70. This establishes nested geometric scale, without creating an appointment at an unsupplied midpoint.",
    "reassessment": "Test the more informative five-node Creation–Terah refinement rather than stopping at bilateral similarity.",
    "checks": {
      "halves": true,
      "scales": true
    },
    "closed_utc": "2026-09-28T01:04:13.636323+00:00",
    "sha256": "eebd35943fcf34a0390ba6b207d01d4c46454ddf6e2ca10563c2efe7cab6071d"
  },
  {
    "step": 648,
    "title": "Recover the five-node Creation refinement",
    "question": "Can one small template reproduce both standard and restored Creation refinements?",
    "inputs": {
      "standard": [
        4121,
        4115,
        4114,
        4108,
        4107
      ],
      "restored": [
        4251,
        4245,
        4244,
        4238,
        4237
      ],
      "template": [
        7,
        1,
        0,
        -6,
        -7
      ]
    },
    "sources": [
      "File70 §§2.3,3.2; A.3"
    ],
    "opened_utc": "2026-09-28T01:04:26.557313+00:00",
    "predecessor_sha256": "eebd35943fcf34a0390ba6b207d01d4c46454ddf6e2ca10563c2efe7cab6071d",
    "results": {
      "generated": [
        [
          4121,
          4115,
          4114,
          4108,
          4107
        ],
        [
          4251,
          4245,
          4244,
          4238,
          4237
        ]
      ],
      "gaps": [
        6,
        1,
        6,
        1
      ],
      "component_translation": [
        130,
        130,
        130,
        130,
        130
      ]
    },
    "finding": "Both Creation states are the same five-position template centered at4114 or4244; regular Cainan changes every coordinate by130 and leaves the6|1|6|1 refinement intact.",
    "reassessment": "Test the complete Terah refinement against this template.",
    "checks": {
      "standard": true,
      "restored": true,
      "translation": true
    },
    "closed_utc": "2026-09-28T01:04:26.557526+00:00",
    "sha256": "55f515ca546e718d153b292e3e2f70d5c297ee2da5b2e4998114b15c6dd4cec4"
  },
  {
    "step": 649,
    "title": "Map Creation’s entire refinement to Terah",
    "question": "Does the tenfold scale preserve all four subdivisions and five roles?",
    "inputs": {
      "creation": [
        4121,
        4115,
        4114,
        4108,
        4107
      ],
      "terah": [
        2296,
        2236,
        2226,
        2166,
        2156
      ],
      "centers": [
        4114,
        2226
      ]
    },
    "sources": [
      "File70 §§2.3,3.2,4.2; A.2–A.3"
    ],
    "opened_utc": "2026-09-28T01:04:38.874545+00:00",
    "predecessor_sha256": "55f515ca546e718d153b292e3e2f70d5c297ee2da5b2e4998114b15c6dd4cec4",
    "results": {
      "mapped": [
        2296,
        2236,
        2226,
        2166,
        2156
      ],
      "terah_gaps": [
        60,
        10,
        60,
        10
      ],
      "normalized_roles": [
        7,
        1,
        0,
        -6,
        -7
      ]
    },
    "finding": "One affine map carries the complete Creation6|1|6|1 refinement into Terah60|10|60|10. The correspondence is between structural positions; the source’s biographical and comparison roles remain distinct.",
    "reassessment": "Determine which broader three-node families are projections of this refined template.",
    "checks": {
      "all_five": true,
      "refinement": true
    },
    "closed_utc": "2026-09-28T01:04:38.874736+00:00",
    "sha256": "982f58d3ce265d83088399737601350b1e213352f64319e8dd8df35e5c84138d"
  },
  {
    "step": 650,
    "title": "Locate the common coarse rail",
    "question": "Which supplied triples share the same bilateral projection?",
    "inputs": {
      "triples": [
        [
          4121,
          4114,
          4107
        ],
        [
          4251,
          4244,
          4237
        ],
        [
          2296,
          2226,
          2156
        ],
        [
          1929,
          1922,
          1915
        ],
        [
          1885,
          1878,
          1871
        ]
      ],
      "centers": [
        4114,
        4244,
        2226,
        1922,
        1878
      ],
      "steps": [
        7,
        7,
        70,
        7,
        7
      ]
    },
    "sources": [
      "File70 §§3–6; A.3,A.5,A.6"
    ],
    "opened_utc": "2026-09-28T01:04:52.873999+00:00",
    "predecessor_sha256": "982f58d3ce265d83088399737601350b1e213352f64319e8dd8df35e5c84138d",
    "results": {
      "normalized": [
        [
          1,
          0,
          -1
        ],
        [
          1,
          0,
          -1
        ],
        [
          1,
          0,
          -1
        ],
        [
          1,
          0,
          -1
        ],
        [
          1,
          0,
          -1
        ]
      ],
      "refinement_projection": [
        0,
        2,
        4
      ]
    },
    "finding": "All five supplied triples normalize to1|0|-1. Creation and Terah additionally share the five-node refinement; Jacob and Joseph establish the coarse rail only. A shared outer shape does not supply missing inner events.",
    "reassessment": "Consolidate the first20 steps into an explanation of geometry versus selected calendar placement.",
    "checks": {
      "all_triples": true,
      "projection": true
    },
    "closed_utc": "2026-09-28T01:04:52.874257+00:00",
    "sha256": "e4c24280b4d4426f3ceec817198a956ebe03ed332b45f3e95d2b601944e35429"
  },
  {
    "step": 651,
    "title": "Consolidate the rail and refinement families",
    "question": "What is the shortest supported explanation after the first20 steps?",
    "inputs": {
      "families": [
        "calendar rails",
        "five-position Creation–Terah refinement",
        "coarse Jacob/Joseph rails"
      ],
      "scope": "source-conditioned geometry"
    },
    "sources": [
      "C632–C650",
      "Research Strategy"
    ],
    "opened_utc": "2026-09-28T01:05:24.402267+00:00",
    "predecessor_sha256": "e4c24280b4d4426f3ceec817198a956ebe03ed332b45f3e95d2b601944e35429",
    "results": {
      "artifact": {
        "path": "deliverables/C651_Interim_Synthesis.md",
        "sha256": "ff98f9808fb24b7648ba2eeb7f8e0a1a23508c84f34e2dae154bb7f095f750ab",
        "bytes": 1119
      },
      "completed_range": [
        632,
        651
      ],
      "core_rules": [
        "Dij=T+7(j−i)",
        "R(c,u)=c+u(7,1,0,−6,−7)",
        "T=2366+32760q"
      ]
    },
    "finding": "Twenty sequential steps now explain two whole-family generators and distinguish their inherited shapes from the source-selected placements. Further scalar boundary searches are lower priority than the prepared reflection and cumulative families.",
    "reassessment": "Reconstruct the source’s Jacob-centered reflection as a complete event-role object.",
    "checks": {
      "range": true,
      "calendar": true,
      "refinement": true
    },
    "closed_utc": "2026-09-28T01:05:24.402497+00:00",
    "sha256": "45e5a551cfa6f6c155c1c4932f71c7c08997ccbf79e0d2110994f1269d2d9e77"
  }
]