s1338.py

from research import *
s=begin(1338,"Prepare the Moses block table","Which named segments jointly generate the cycle spans?",{},["C1232–C1252"])
t=json.loads("\"## Rounded rows form the Moses family\\n\\nThe Moses-centred construction uses the MT Terah-70, Cainan-OFF state, excludes the separate Shem +2 convention, and holds Moses at 1526 BC. It follows an ordered Regular chronological path. Its late edges include events as well as begetting ages: Jacob is 91 at Joseph’s birth, Joseph is 39 at Entry, and Entry precedes Moses by 350. Row rounding gives 90, 40 and 350, preserving their combined 480.\\n\\nThe complete path contains twenty-five nodes. Five named blocks expose its structure:\\n\\n| Segment | Exact sum | Sum of rounded rows | Exact minus Rounded |\\n|---|---:|---:|---:|\\n| Adam → Seth | 130 | 130 | 0 |\\n| Seth → Enoch | 492 | 490 | 2 |\\n| Enoch → Arphaxad | 1034 | 1030 | 4 |\\n| Arphaxad → Reu | 129 | 130 | −1 |\\n| Reu → Moses | 801 | 800 | 1 |\\n| **Adam → Moses** | **2586** | **2580** | **6** |\\n\\nThe whole Rounded path gives \\\\(2580=6\\\\times430\\\\). Removing its first block gives Seth-to-Moses \\\\(2450=5\\\\times490\\\\); removing the next gives Enoch-to-Moses \\\\(1960=4\\\\times490\\\\). These are connected measurements of one reconstructed path.\\n\\nThe post-Flood partition is especially revealing: exact \\\\(129+801\\\\) becomes Rounded \\\\(130+800\\\\), reproducing the two parts of Adam’s selected life while retaining the total 930. Eber, Reu and Nahor’s rounding residuals account for the internal shift, with the Jacob/Joseph residuals cancelling later. The relationship belongs to the selected path and its rounding rule.\\n\\nSource basis: File18, File51a and File52c; C1232–C1252.\\n\"")
a=artifact("draft/05a_Moses_blocks.md",t)
finish(s,{'artifact':a,'words':len(t.split())},"The block table makes the 430/490 cycles and Adam-part correspondence consequences of one named path.","Explain residual recovery and variant scope for the Moses path.",{'nonempty':len(t)>100,'cycles':2580==6*430 and 2580-130==5*490 and 2580-130-490==4*490})