from research import *
s=begin(1180,'Cost the first block’s explanatory gains','Which results reduce a declared source model and which are consistency or new encodings?',{},['C1132–C1179','Strategy §§1,6'])
ledger=[
['SP age relations','three explicit age constraints; three reverse-cap equations separately supplied','remaining65 scale and two interior ages; cap outputs not independent if generated from same input'],
['SP capacity/slack law','one threshold mechanism explains all9 lifespan outputs from located birth changes','baseline lives, age-change locations and counting conventions'],
['postFlood row triangle','same R/A moves organize every9-row source comparison','triangle closure forced; named supports and amplitudes supplied'],
['postFlood shared amplitudes','36 located changes represented by3 parameters','18 baseline inputs retained; mask and exception costs explicit'],
['baseline equalities','four selected equalities lower the joint native model from21 to17','not an exhaustive minimum; no historical independence'],
['nativeCainan equality','shares130/330/460 numeric vector withShelah','person existence and insertion position retained'],
['rank-only counterexample','shows why dimension alone is insufficient','56 stored coefficients can hide all data in a rank1 rule'],
['whole genealogy extension','pre/post century changes use different conserved components','Lamech−24 and fitted Eber40+Nahor60=100 relation remain explicit']]
a=artifact('model/block1_explanation_cost_ledger.json',json.dumps(ledger,indent=2)+'\n')
finish(s,{'first_block_cost_ledger':a,'explanatory_families':len(ledger)},'The block advances the source-generation question through located threshold behavior and a complete row-operation grammar. It leaves inherited magnitudes and source roles visible, rejects rank-only scoring, and sets up a full-genealogy test.','Close the50-action checkpoint, then reread every section of the Strategy before selecting C1182.',{'eight_families':len(ledger)==8,'no_new_endpoint_search':all('new endpoint' not in x[1] for x in ledger),'cost_present':all(x[2] for x in ledger)})
